Changes between Version 3 and Version 4 of GEC15Agenda/AdvancedGENITopoOmni/Instructions/TopologyExperiment


Ignore:
Timestamp:
10/21/12 22:43:33 (7 years ago)
Author:
nriga@bbn.com
Comment:

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  • GEC15Agenda/AdvancedGENITopoOmni/Instructions/TopologyExperiment

    v3 v4  
    7676}}}
    7777
    78 ==== Test login ====
    79 For each one of the myPlc hosts, open a new terminal and login to each one of them. Substitute <pl_hostname> with the hostnames of pl nodes you were given on the paper slip.
    80 {{{
     78  i. Login to your hosts. For each one of the myPlc hosts, open a new terminal and login to each one of them. Substitute <pl_hostname> with the hostnames of pl nodes you were given on the paper slip.
     79  {{{
    8180  ssh <pl_hostname>
    8281}}}
     
    8988First of all let's see how we can figure out the IP of the hosts we reserved :
    9089
    91    * List all the interfaces on your host. You will see that there are many interfaces of the form eth1.XXXX
     90   i. List all the interfaces on your host. You will see that there are many interfaces of the form eth1.XXXX
    9291   {{{
    9392   /sbin/ifconfig
     
    104103   }}}
    105104
    106    * Figure out the last octet of the IP address of your hosts. The way these MyPLC hosts are setup, is that they have multiple subinterfaces, each configured to be part of a different IP subnet. Almost all subnets in the hosts are in the form of 10.42.Y.0/24. You will notice that for all these subnets, your host has the same last octet.  In the example above all the subinterfaces of eth1, will have an IP address that will end in '''90''' (10.42.147.'''90''', 10.42.148.'''90''')
     105   i. Figure out the last octet of the IP address of your hosts. The way these MyPLC hosts are setup, is that they have multiple subinterfaces, each configured to be part of a different IP subnet. Almost all subnets in the hosts are in the form of 10.42.Y.0/24. You will notice that for all these subnets, your host has the same last octet.  In the example above all the subinterfaces of eth1, will have an IP address that will end in '''90''' (10.42.147.'''90''', 10.42.148.'''90''')
    107106
    108    * Ping over 3715. After logging in to your hosts, ping from host1 to host2. Assuming that host2 has a last octet of YYY you should:
     107   i. Ping over 3715. After logging in to your hosts, ping from host1 to host2. Assuming that host2 has a last octet of YYY you should:
    109108   {{{
    110109ping 10.42.112.YYY
     
    112111   Notice the RTT on the packets.
    113112
    114    * Ping over 3716. After logging in to your hosts, ping from one host2 to host1. Assuming that host1 has XXX as it's last octet you should ping
     113   i. Ping over 3716. After logging in to your hosts, ping from one host2 to host1. Assuming that host1 has XXX as it's last octet you should ping
    115114   {{{
    116115ping 10.42.113.XXX
    117116   }}}
    118    * Notice the RTT on the packets and compare it with the above ping.
     117   i. Notice the RTT on the packets and compare it with the above ping.
    119118
    120119== 7. Clean up ==